A metal cube of mass 460g and density 2.7g/cm cube is suspended half immersed in a liquid og density 0.8g/cm cube using a thread. Find the tension in the thread.
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Answer:
Tension = 3.84N
Explanation:
since ' a ' = 0
=> F net external = 0
=> weight of cube = tension + upthrust
weight = mg
460g = 46/100 kg
=> weight = 46g/100 N
volume = mass / density
density = 2.7 g/cm^3 = 2700 kg/m^3
=> volume of cube = 46/270000 m^3
ATQ;
volume of solid submerged = 1/2 x 46/270000 m^3
Upthrust = volume of solid submerged x density of liquid x g
=> U = 1/2 x 46/270000 x 800 x g
=> U = 184g/2700 N
Tension = 46g/100 - 184g/2700
= 1058g/2700
Taking g as 9.8 m/s^2
Tension = 1058*9.8/2700
= 3.84 newtons ( approx.)
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