Question

a metal cube of side 10cm is subjected to a shear stress 10*4N/m×m calculate the rigidity modulus if the top of the cube is displaced by 0.5 cm with respect to its bottom​

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A metal cube of side 10cm is subjected to a shearing stress of 104Nm−2. The modulus of rigidity if the top of the cube is displaced by 0.05cm with respect to its bottom is

A

2×106Nm−2

B

105Nm−2

C

1×107Nm−2

D

4×105Nm−2

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Correct option is

A

2×106Nm−2

We know that shearing stress=AF=104Nm−2

Length of side of cube=10cm=10010m=0.1m

Shearing displacement=△n=0.05cm

=1000.05m=0.0005m

We know that modulus of rigidity is η=AθF

=