Question

A metal cube of side 2 cm. and density 7.9 g/cm^3 is suspended by a thread and immersed completely in water. Find the tension in the thread​

Answer 1

Side of the cube =5 cm

So, its volume , V=a

3

=125 cm

3

Mass of cube =V×d=125×9=1125 g

Weight =mg=1125×1000=1125000 dyne

Now, cube is immersed is liquid,

∴ buoynat force =Vρg=125×1.2×1000=150000 dyne

So, Tension = apparent weight =(1125000−150000) dyne=975000 dyne=9.75 N

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Answer 2

Explanation:

Mg = Buoyant Force + Tension

Mass of the object × g = Density of water × Volume immersed × g + Tension

Mass of the object = Density of the object × Volume of the object.

63.2 × 10 = 1 × 8 × 10 + Tension

632 = 80 + Tension

Tension = 552 N

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