Question

A metal cube of side 5 cm and density 7.9g/cm³ is suspended by a thread and is immersed completely in a liquid of density 1.1g/cm³. Find the tension in thread

Answer 1

Volume of metal cube = (5 cm)3 = 125 x 10−6 m3.
Density of metal = 9 g/cm3 = 9000 kg/m3.
Mass of the metal cube m = volume x density 
                                      = 125 x 10−6 m3.9000 kg/m3.
                                       = 1.125 kg
Weight of the metal cube in air = mg = 1.125 kg x 10 m/s2 = 11.25 N

Volume of liquid displaced = Volume of metal cube = 125 x 10−6 m3.
Mass of liquid displaced = Volume x density of liquid 
                                       = 125 x 10−6 m3.1200 kg/m3.
                                       =  0.15 kg
Weight of liquid displaced = 0.15  kg x 10 m/s2 = 1.5 N = upthrust

Weight of metal cube in liquid = Weight of the metal cube in air - upthrust
                                                = 11.25 − 1.5 
                                                =  9.75 N
Therefore tension in the string = 9.75 N.

Similarly you can calculate the quantities in the next problem.
Pl. ask only one question under one question id.

Answer 2

Answer:

6.75N

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