A metal cuboid of mass M kg rests on a table surface are of 40M/kg² in contact with the table. The pressure exerted by the cuboid on the table surface is 10000Pa. Value of Mis (given that g=10M/kg-²)
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4kg
Step-by-step explanation:
A = 40 cm2 = 40×10-4
m2pressure = 10000
paforce = weight = mgforce = pressure×areamg = 10000×40×10-4m
= 40/10
= 4 kg
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