Question

A metal forms fcc arrangement and if the volume of oremetal is x ml

Answer 1

862/1.414 = 609.6 pm

Explanation- two atoms touch each other at the diagnol of the side.

So length of diagnol = 862 x 1.414 = y

and distance b/w two nuclei

Answer 2

A metal forms an fcc arrangement and if the volume of ore metal is x ml and has four atoms, eight corners, and six half in the faces.

Explanation:

• In fcc, there are 8 atoms at the corners of the unit cell one atom will be centered in each of the faces.
• Atoms are shared with the adjacent cell.
• They have four atoms, eight corners, and six half in the faces.
• They are more ductile than bcc.
• In face-centered cubic, a unit cell (n)=4
• So, the total volume in fcc = 4 x V
• so the volume will be 4 X 4/3∏r³= 16/3∏r³
• The volume of sphere = 4/3∏r³