Question

A metal forms two oxides. The higher oxide
contains 80% metal. 0.72 g of the lower oxide gave
0.8 g of higher oxide when oxidised. Then the ratio
of the weight of oxygen that combines with the
fixed weight of the metal in the two oxides will be?
Please explain step by step in detail.​

Answer 1

Answer:

In higher oxide

Wt of metal= 0.8x80/100=0.64g

Wt. Of oxygen=0.8-0.64=0.16g

In lower Oxide

Wt. of metal will remain the same as in higher oxide=0.64g

wt. of oxygen =0.72-0.64=0.08g

The ratio of weight of oxygen which combines with a fixed weight of metal in two oxides is

0.16:0.08

2:1

As it is a whole number ratio . The law of multiple proportion is illustrated.

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