Question

A metal has a body centred cubic crystal structure the density of metal is

Answer 1

Answer:

we can take example of Li

For the bcc structure, Z = 2

Edge of unit cell , a = ?

Density of the element,r = 0.53 g/cm3

r = Z  X  M

    a3  X N0

0.53g/cm3 = 2 X  6.94g/mol

                   a3  X 6.022 X 1023mol-1

a3 = 4.34 X 10-23

a = 0.351 X 10-7cm

Explanation:

Answer 2

Answer:

we can take example of Li

we can take example of LiFor the bcc structure, Z = 2

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M    a3  X N0

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M    a3  X N00.53g/cm3 = 2 X  6.94g/mol

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M    a3  X N00.53g/cm3 = 2 X  6.94g/mol                   a3  X 6.022 X 1023mol-1

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M    a3  X N00.53g/cm3 = 2 X  6.94g/mol                   a3  X 6.022 X 1023mol-1a3 = 4.34 X 10-23

we can take example of LiFor the bcc structure, Z = 2Edge of unit cell , a = ?Density of the element,r = 0.53 g/cm3r = Z  X  M    a3  X N00.53g/cm3 = 2 X  6.94g/mol                   a3  X 6.022 X 1023mol-1a3 = 4.34 X 10-23a = 0.351 X 10-7cm

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