A metal has a simple cubic lattice. The edge length of the unit cell is 400pm. If the molar mass of the metal is 64g mol^-1 , then the approximate density of the unit cell is
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Given:
The metal forms a simple cubic structure.
a = 400 pm = 4 × 10⁻⁸ cm
Molar mass of metal = 64 gm
To Find:
The density (d) of the unit cell of metal.
Calculation:
- NA = 6.022 × 10²³
- For simple cubic structure, z = 1
- V = a³ = (4 × 10⁻⁸)³
⇒ V = 64 × 10⁻²⁴ cm³
- We know the formula:
V × NA × d = z × M
⇒ d = (z × M)/(V × NA)
⇒ d = (1 × 64)/(64 × 10⁻²⁴ × 6.022 × 10²³)
⇒ d = 1 / (6.022 × 10⁻¹)
⇒ d = 1.66 gm/cm³ ≈ 1.7 gm/cm³
- So, the correct option is (a) 1.7 gm/cm³.
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