Question

A metal having work function = 4.41 x 10 ^-19 J is subjected to a light having a wavelength 300 nm, then the maximum kinetic energy of the emitted. Photoelectron is .........x 10^-21 J.

Answer 1

Answer:

• 2.19×10^-19.....

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Answer 2

ANSWER:

• The maximum kinetic energy of the emitted Photoelectron = 221.6 × 10⁻²¹ J.

GIVEN:

• A metal having work function = 4.41 x 10⁻¹⁹ J

• It is subjected to a light having a wavelength 300 nm,

TO FIND:

• The maximum kinetic energy of the emitted Photoelectron.

EXPLANATION:

$\sf W_o= 4.41 \times 10 ^{-19}\ J$

$\sf Wavelength(\lambda) = 300 \ nm$

$\boxed{ \bold{ \large{ \gray{ K.E_{max} =E -W_0}}}}$

$\boxed{ \bold{ \large{ \gray{E =\dfrac{hc}{\lambda}}}}}$

$\sf h = 6.626 \times 10^{-34} \ Js$

$\sf c = 3 \times 10^8\ ms^{-1}$

$\sf \lambda= 300 \ nm = 300 \times {10}^{ - 9} \ m$

$\sf E =\dfrac{6.626 \times 10^{-34} \times 3 \times 10^8}{300 \times {10}^{ - 9} }$

$\sf E =\dfrac{6.626 \times 10^{-34} \times 10^8}{100 \times {10}^{ - 9} }$

$\sf E =\dfrac{6.626 \times 10^{ - 26}}{{10}^{ - 7} }$

$\sf E =6.626 \times 10^{ - 26 + 7}$

$\sf E =6.626 \times 10^{ -19} \ J$

$\sf E -W_0 = 6.626 \times 10^{ -19} - 4.41 \times 10 ^{-19}$

$\sf E -W_0 =( 6.626 - 4.41)\times 10 ^{-19}$

$\sf E -W_0 =2.216 \times 10 ^{-19}\ J$

$\sf E -W_0 =221.6 \times 10 ^{-21}\ J$

$\sf K.E_{max} =221.6 \times 10 ^{-21}\ J$

HENCE THE MAXIMUM KINETIC ENERGY = 221.6 × 10⁻²¹ J.

OTHER FORMULAE FOR MAXIMUM KINETIC ENERGY:

$\sf K.E_{max}= \dfrac{1}{2}mv^2_{max}$

$\sf K.E_{max}=h(\nu-\nu_o)$

$\sf K.E_{max}= h\left(\dfrac{c}{\lambda}-\dfrac{c}{\lambda_o}\right)$