Chemistry, asked by suhas8102, 17 days ago

A metal M exists in two forms Mb+ and Ma+ (b > a). When a current of 2 A is passed through a 1 L aqueous solution of 0.01 M Mb+ for 965 s, 0.005 mol of the metal was deposited at the cathode while the concentration of Ma+ in solution was found to be 0.005 M. Assuming that the reduction process takes place stepwise and equal moles of electrons are consumed in both the reduction reactions, find the value of a × b.

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Answered by nisthamahaseth
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