Chemistry, asked by Yuvian7483, 9 months ago

A metal M forms a metal Carbonate M2Co3 of the carbonate contains 48%oxygen by mass then determine the atomic weight of metal

Answers

Answered by mohitbadgujar06
0

Answer:

M is 20

Explanation:

Mass % of O=48%

Mass % of O=48%Let the atomic mass of M be x

Total mass = 2y+12+48

Total mass = 2y+12+48=(2y+60)g/mol

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)100

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048 ×(2y+60)=48

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048 ×(2y+60)=4896y+2880=4800

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048 ×(2y+60)=4896y+2880=480096y=1920

Total mass = 2y+12+48=(2y+60)g/molO is 48% of the total mass.∴48% of (2y+60)10048 ×(2y+60)=4896y+2880=480096y=1920y=20

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