Question

A metal M has quite a low position in the reactivity series. Its main ore is cinnabar. Which method will be used to concentrate the ore and why? [Class-X. Ch-3-Metals and Non-Metals]...pls answer fast

Answer 1

Here is your answer:

Here metal M is Mercury.

We use roasting method because in this process we provide heat to the ore in the presence of oxygen. The reaction involved in this is:

2HgS (s) + 3O2(g) (heat) —> 2HgO (s) + 2SO2 (g)

Then mercuric oxide is further heated

2HgS (s) (heat) —> 2Hg(l) + O2 (g)

HOPE IT HELPS YOU.

Answer 2

Metal M is $\underline{\large{\texttt{Mercury}}}$.

We use Roasting method because in this process we provide heat to the ore in the presence of oxygen. The reaction involved in this is:

$2HgS (s) + 3O_2(g) (heat) \longrightarrow 2HgO (s) + 2SO_2 (g)$

Then mercuric oxide is further heated.

$2HgS (s) (heat) \longrightarrow 2Hg(l) + O_2 (g)$