A metal 'M' is irradiated with a radiation of wavelength 'λ' and intensity 'I'. The number of photoelectrons emitted per second is N and the average kinetic energy of the photoelectrons is E. What would the charge in N and E: i) if I is doubled? ii)if λ is halved?
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Rate of emission of electron is independent of wavelength. Hence, 'x' will be unaffected.
Kinetic energy of photoelectron = Absorbed energy − Threshold energy
y=
λ
hc
−w
0
when, λ is halved, average energy will increase but it will not become double.
(b) Rate of emission of electron per second 'x' will become double when intensity I is doubled. Average energy of ejected electron, i.e., 'y' will be unaffected by increase in the intensity of light.
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