Question

a metal M of equivalent mass e forms an oxide of molecular formula MxOy. the atomic mass of the metal is given by the correct equation

Answer 1

The metal oxide is MxOy

Let p be the at.mass of the metal

Wt of metal = px

Wt of oxygen = 16y

8 g of oxygen wil combine with 8px/16y = px/2y gm

eq. mass of metal e = px/2y

p = 2ey/x

At mass of metal = 2ey/x gm

Answer 2

Answer:

The correct answer to this question is $\frac{2yE}{x}$

Explanation:

Given - A metal M of equivalent mass e forms an oxide of molecular formula MxOy.

To Find - Write the atomic mass of the metal.

The mass of one equivalent is defined as the mass of a substance that will combine with or displace a fixed quantity of another substance.

The valence of oxygen is −2

The Valance of y of oxygen is −2y

Let the valence of M is +P

Charge on x molecule of M is + Px

The compound is neutral = −2y+ Px = 0

$P = \frac{2y}{x}$

The valence of metal M is $\frac{2y}{x}$  and the atomic mass of M is $\frac{2y}{x} E$

So, the atomic mass of M is $\frac{2yE}{x}$.

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