A metal 'M' of moderate reactivity is present
as its sulphide 'X'. On heating in air, 'X'converts into its oxide 'Y' and a gas evolves. On
heating ‘Y' and 'X'together, the metal 'M' is
produced. X' and 'Y' respectively are -
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Answer:
2Cu2S+3O2→Cu2O+2SO2
Metal M is copper
X is cuprous sulphide Cu2S and Y is cuprous oxide Cu2O
2Cu2O+Cu2S→6Cu+SO2
This is an self reduction reaction
Explanation:
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Answered by
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ANSWER
This is an self reduction reaction
Metal M is copper X is cuprous sulphide Cu 2S
and Y is cuprous oxide Cu 2O
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