Chemistry, asked by mmm9582, 1 year ago


A metal 'M' of moderate reactivity is present
as its sulphide 'X'. On heating in air, 'X'converts into its oxide 'Y' and a gas evolves. On
heating ‘Y' and 'X'together, the metal 'M' is
produced. X' and 'Y' respectively are -​

Answers

Answered by anushka52622
6

Answer:

2Cu2S+3O2→Cu2O+2SO2

Metal M is copper

X is cuprous sulphide Cu2S and Y is cuprous oxide Cu2O

2Cu2O+Cu2S→6Cu+SO2

This is an self reduction reaction

Explanation:

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Answered by 22snehomg
1

ANSWER

This is an self reduction reaction

Metal M is copper  X is cuprous sulphide Cu  2S

and Y is cuprous oxide Cu  2O

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