A metal nitrate 'A' on heating gives yellowish brown colored metal oxide along with brown gas 'B' and a colorless gas 'C'. Aqueous solution of 'A' on reaction with potassium iodine forms a yellow precipitate of compound 'D'. Identify A,B,C,D. Identify the types of both reaction. Metal present in A is used in making paints.
Answers
Answered by
144
Answer:
A= Lead nitrate
It is a metal which gives yellowish brown colored metal oxide along with NO2. Lead nitrate is used in the manufacture of paints.
B=NO2 gas
No2 (nitrogen dioxide) is the compound formed as a product when lead nitrate is heated.
i. It has the molar mass number as 46.06g/mol.
ii. It is mostly a gas which appears in brown in color.
iii. It also has the density value of 1.880g dm^-3.
iv. It is soluble in nitric acid.
C=O2 gas
Oxygen gas is a colorless gas formed here in the above chemical equation as a product when lead nitrate on heating.
ii. It is one of the components in the earth.
iii. It exists in many wide variety of colors.
D=lead iodide.
Answered by
66
Answer:
A= Lead nitrate
B=NO2
C=O2 gas
D=lead iodide.
Similar questions