Question

A metal nitride m3n2 contains 28 % of nitrogen. The atomic mass of metal m is

Answer 1

Answer:

Let the mass of compound is 100 g

mass of nitrogen = 28 g

mass of metal = 72 g

as required, let the atomic mass of metal be "x" u

Atomic mass of nitrogen = 14 u

so, 3x + (2*14) = 100

3x = 100 - 28

3x = 72 

x = 24

 therefore atomic mass of Metal is 24 u.

Answer 2

Given:

A metal nitride $M_3N_2$ contains 28 % of nitrogen.

To find:

The atomic mass of the metal.

Solution:

The metal nitride is as follows $M_3N_2$.

Let the atomic mass of the metal M is x grams.

The atomic mass of the N atom is 14 grams.

Hence the percentage of nitrogen in $M_3N_2$ is given as-

$\frac{14 \times 2}{14 \times 2 + 3 \times x} \times 100 = 28 \\ \frac{28}{28 + 3x} \times 100 = 28 \\ 28 + 3x = 100 \\ 3x = 72 \\ x = 24$

The value of x is 24.

Hence the atomic mass of the metal M is 24 grams.