Question

A metal oxide P reacts with water and forms a metal hydroxide Q. On the other hand, a gas R is obtained
at a anode during the electrolysis of brine. Now, when R is passed over dry Q it gives compound S
which is used for disinfecting drinking water.​

Answer 1

P is CaO

Q is Ca(OH)₂

R is Cl₂

S is Ca(OCl)₂

Explanation:

• We know that on electrolysis of Brine solution, at the anode, Chloride ion is oxidised to Chlorine gas (Cl₂)

• Therefore, R is Cl₂

• When R Cl₂ is passed over dry Q then compound S is obtained which is used to disinfecting drinking water

• Therefore, the compound S can be bleaching powder [Ca(OCl)₂]

• In this case the the compound Q which is a metal hydroxide will be Ca(OH)₂

• Therefore, the metal oxide P will be CaO

The equations will be

CaO + H₂O → Ca(OH)₂

NaCl → Na⁺ + Cl⁻

Cl⁻ + Cl⁻ → Cl₂ + 2e⁻

2Ca(OH)₂ + 2Cl₂ → Ca(OCl)₂ + CaCl₂ + 2H₂O

The process of obtaining Cl₂ is known as chloralkali process

Cl₂ is used as disinfectant both for drinking water and swimming pool water

Cl₂ is used as bleaching agent

Hope this answer is helpful.

Know More:

Q: A metal carbonate X on reacting with an acid gives a gas which when passed through a solution Y gives the carbonate back. On the other hand, a gas G that is obtained at anode during electrolysis of brine is passed on dry Y, it gives a compound Z, used for disinfecting drinking water. Identity X, Y, G and Z

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