Question

A metal piece of mass 100 g is heated to raise its temperature to 100°C. it is then added to water of mass 200 g and temperature 20°C in a copper calorimeter. The mass of copper is 0 50 g and its specific heat is 0.1 cal/g°C. After stirring the water, the highest temperature

0 recorded is 25°C. Calculate the specific heat of the metal.​

Answer 1

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Answer 2

Answer:

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VIDEO EXPLANATION

ANSWER

The amount of heat last by copper ball =m

ball

C

Cu

ΔT

ball

=(100gm)(0.1cal/gm˚C)(T−75)˚C

The amount of heat gained by calorimeter =m

calorie

C

Cu

ΔT

Calorie

=(100gm)(0.1cal/gm˚C)(75−30)˚C

Amount of heat gained by water =m

w

C

Cu

ΔT

w

(170gm)(1cal/gm˚C)(75−30)˚C

Hence, from conservation of energy,

100×0.1×(T−75)=100×0.1×(75−30)+170×1×(75−30)

⇒T=885˚C