A metal piece weight 200 gf in air and 150 gf when completely immersed in water 1 calculate the relative density of the metal piece 2 how much will it weight in a liquid of density 0.8 g
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Answer:(I). , (II).
Explanation:
Given that,
Weight of metal piece in air
Weight of metal piece in water
We know that,
Mass = Volume X Density
Weight in air ,
....(I)
Weight in water,
= upthrust force
We know that,
Upthrust of water = apparent loss of weight of solid = weight in air - weight in liquid
We know that,
.....(II)
Now, volume of the solid
Now, divided equation (I) by (II)
(I). The relative density of the metal piece is
(II). The weight in liquid when density
Weight in liquid
Hence, this is the required solutions
Answer:(I). , (II).
Explanation:
Given that,
Weight of metal piece in air
Weight of metal piece in water
We know that,
Mass = Volume X Density
Weight in air ,
....(I)
Weight in water,
= upthrust force
We know that,
Upthrust of water = apparent loss of weight of solid = weight in air - weight in liquid
We know that,
.....(II)
Now, volume of the solid
Now, divided equation (I) by (II)
(I). The relative density of the metal piece is
(II). The weight in liquid when density
Weight in liquid
Hence, this is the required solutions
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