Physics, asked by pritambasu1009, 9 months ago

A metal piece weight 44.5 g in air, 39.5g in water and 40.3 g in an oil. find the R.D. of the metal and the oil.​

Answers

Answered by Anonymous
3

Answer:

Wa = weight of iron piece in air

Ww = weight of iron piece in water

normally relative density is calculated wrt  water.

relative density of iron piece =  Wa / (Wa - Ww)

         = weight in air / Loss of weight in water

         = 44.5 / (44.5 - 39.5) = 8.9

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if weight in oil is also known then you could calculate relative density of oil also.

relative density of oil = (Wa - Woil) / (Wa - Ww)

hope it helps :)

Answered by aadishree7667
4

holla dued please refer pic above

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