Question

A metal pipe is 77 cm long the inner diameter of a cross section is 4 cm , the outer diameter being 4.4 cm find inner ​

Answer 1

Answer:

$\sf{1)inner \: curved \: surface \: area = {968cm}^{2}}$

$\sf{2)outer \: curved \: surface \: area = 1064.8 {cm}^{2}}$

$\sf{3)total \: surface \: area = {2038.08cm}^{2}}$

Step-by-step explanation:

$\sf{1)diameter = {d_{1}} = 4cm}$

$\sf{radius = \frac{d_{1} }{2}} = \frac{4}{2} = 2cm$

$\sf{height = 7cm}$

$\sf{inner \: curved \: surface \: area = 2\pi rh}$

$\sf{ = 2 \times \frac{22}{7} \times 2 \times 77}$

$\sf{ = 986 {cm}^{2}}$

$\sf{2)outer \: curved \: surface \: area}$

$\sf{diameter =d_{2} = 4.4cm}$

$\sf{radius = \frac{4.4}{2} = 2.2cm}$

$\sf{height = 77cm}$

$\sf{outer \: curved \: surface \: area = 2\pi rh}$

$\sf{ = 2 \times \frac{22}{7} \times 2.2 \times 77}$

$\sf{ = 1064.8 {cm}^{2}}$

$\sf{3)total \: surface \: area}$

$\sf{area \: of \: the\: base (base \: is \: a \: concentric \: circle)}$

$\sf{ = 2\pi( {R}^{2} - {r}^{2})}$

$\sf{ = 2 \times \frac{22}{7}((2.2)^{2} - ( {2}^{2}))}$

$\sf{ = 22 \times \frac{22}{7}(4.84 - 4)}$

$\sf{ = total \: surface \: area(tsa) \: of \: the \: given \: cylindrical \: pipe = inner \: curved \: surface \: area + outer \: curved \: surface \: area + area \: of \: the \: both \: bases}$

$\sf{ = {986cm}^{2} + {1064cm}^{2} + {5.28cm}^{2}}$

$\sf{ = {2038.08cm}^{2}}$

$\bf \pink{ \underline{please \: mark \: it \: as \: brainlist \: answer}}$