A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4cm. (see fig. 13.11). Find its
(i) inner curved surface area,
(ii) outer curved surface area
(iii) total surface area
(Assume π=22/7)
Answers
Answered by
0
Step-by-step explanation:
option 3 total surface area.
Answered by
1
Step-by-step explanation:
i) Inner radius of cylindrical pipe = r1=
Inner diameter
2
cm = 2 cm
Height (h) of cylindrical pipe = 77 cm
Curved Surface Area of inner surface of pipe = 2πr,h
= (2 x (22/7) x 2 x 77) cm2
= 968 cm²
ii) Outer radius of cylindrical pipe =r 2
=
Outer diameter/2
=
(4.4/2) cm = 2.2 cm
Height of cylinder = h = 77 cm
Curved Surface Area of outer surface of pipe = 2πr 2 h
= (2x(22/7) 2.2 x 77) cm²
= (2 x 22 x 2.2 X 11) cm²
= 1064.8 cm²
Hope this helped you.. :)
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