A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.8 cm.
Find its:
o
(i) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.
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Answers
Answer:
(i) Height of pipe = 77cm
Inner radius of pipe = 4/2 = 2cm
Inner curved surface area = 2πrh
= 2×22/7×2×77
= 2×22×2×11
= 44×22
= 968cm²
(ii) Height of pipe = 77cm
Outer radius of pipe = 4.8/2 = 2.4cm
Outer curved surface area = 2πrh
= 2×22/7×2.4×77
= 2×22×2.4×11
= 44×26.4
= 1161.6cm²
(iii) Total surface area =
Inner CSA + Outer CSA +2π (R²- r²)
968 + 1161.6 + 2×22/7 [(2.4)² - (2)²]
2129.6 + 44/7 (5.76-4)
2129.6 + 6.28×1.76
2129.6 + 11.05
2140.65cm²
Answer:
inner curved surface area,
option A
is correct ans