A metal pipe is 77 cm long. The inner diameter of a cross
section is 4 cm, the outer diameter being 4.4 cm
(see Fig. 13.11). Find its
(i) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.
Fig. 13.11
Answers
Step-by-step explanation:
Given:-
A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm
To find:-
Find its
(i) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.
Solution:-
Length of the metal pipe = 77cm
Height of the metal pipe (h)=77cm
Diameter of the inner pipe = 4 cm
Radius of the inner pipe (r)=diameter/2
Radius of the inner pipe = 4/2 = 2 cm
Let r = 2 cm
Diameter of the outer pipe = 4.4 cm
Radius of the outer pipe(R)=4.4/2 = 2.2 cm
Let R = 2.2 cm
I) Curved Surface Area of a Cylinder =
2πrh sq.units
Inner Curved Surface Area of the pipe
=>2×(22/7)×2×77 sq.cm
=>(2×22×2×77)/7 sq.cm
=>2×22×2×11 sq.cm
=>968 sq.cm ---------------(1)
Inner Curved Surface Area of the cylindrical pipe = 968 sq.cm
ii) Outer Curved Surface Area of the pipe
=2πRh sq.units
=>2×(22/7)×2.2×77 sq.cm
=>(2×22×2.2×77)/7 sq.cm
=>2×22×2.2×11 sq.cm
=>1064.8 sq.cm------------(2)
The base of the cylinder is a circle
The base of cylindrical pipe is a ring shaped figure
Area of the base = Area of the top
= π(R+r)(R-r) sq.units
Here , R = 2.2 cm and r = 2 cm
=>(22/7)(2.2+2)(2.2-2) sq.cm
=>(22/7)(4.2)(0.2) sq.cm
=>(22×4.2×0.2)/7 sq.cm
=>22×0.6×0.2 sq.cm
=>2.64 sq.cm
Area of the base = 2.64 sq.cm------------(3)
Area of the top = 2.64 sq.cm-------------(4)
iii) Total Surface Area of the given cylindrical pipe
=Inner Curved Surface Area+ Outer Curved surface Area+Area of the base +Area of the top
From (1),(2),(3)&(4)
=>TSA = 968+1064.8+2.64+2.64 sq.cm
TSA = 2038.08 sq.cm
Answer:-
i)Inner Curved Surface Area of the cylindrical pipe = 968 sq.cm
ii)Outer Curved Surface Area of the pipe
=1064.8 sq.cm
iii)Area of the base = 2.64 sq.cm
iv)Area of the top = 2.64 sq.cm
v)Total Surface Area of the given cylindrical pipe =
2038.08 sq.cm
Used formulae:-
- Curved Surface Area of a Cylinder =
- 2πrh sq.units
- Area of the base = Area of the top of a cylindrical pipe = Area of the ring = π(R+r)(R-r) sq.units
- Total Surface Area of the given cylindrical pipe=Inner Curved Surface Area+ Outer Curved surface Area+Area of the base +Area of the top