a metal pipe is 77 cm long the inner diameter of the cross section is 4 cm and the outer diameter is 4.8 cm find its inner curved surface area, outer curved surface area and total surface area
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r=2cm
R=2.4cm
Inner CSA=
= 2*22/7*2*77
=968cm^2
Outer CSA=
=2*22/7*2.4*77
=1161.6cm^2
TSA=inner CSA+outer CSA+two base area
two base area=[tex]2( \pi R^2- \pi r^2) =2 \pi (R^2-r^2)[/tex]
= 2*22/7((2.2)^2-(20^2)
=2*22/7*4.2*0.2
=5.28cm^2
TSA =968+1161.6+5.28
=2134.88cm^2
R=2.4cm
Inner CSA=
= 2*22/7*2*77
=968cm^2
Outer CSA=
=2*22/7*2.4*77
=1161.6cm^2
TSA=inner CSA+outer CSA+two base area
two base area=[tex]2( \pi R^2- \pi r^2) =2 \pi (R^2-r^2)[/tex]
= 2*22/7((2.2)^2-(20^2)
=2*22/7*4.2*0.2
=5.28cm^2
TSA =968+1161.6+5.28
=2134.88cm^2
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