A metal pipe is 77 cm long.,the inner diameter of the cross section is 4 cm and outer diameter is 4.8cm.find inner curved surface area,outer curved surface area and total surface area.plzzzz ans this
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H=77
2r=4cm,⇒r=2cm
2R=4.4cm,⇒R=2.2
CSA of inner cylinder =2πrh
2×22÷7×2×77
44×22=968cm₂
CSA of outer cylinder=2πrh
2×22÷7×2.4×77
1064.8cm₂
TSA of cylinder =2πRh+2πrh(R₂-r₂)
1064.8+2×22÷7×2×77+2×22÷7×[(2.2)₂-(2)₂]
1064.8+968+2×22÷7×(4.84-4)
1064.8+968+2×2×22÷7×0.84
1064.8+968+5.28=2038.08cm₂
2r=4cm,⇒r=2cm
2R=4.4cm,⇒R=2.2
CSA of inner cylinder =2πrh
2×22÷7×2×77
44×22=968cm₂
CSA of outer cylinder=2πrh
2×22÷7×2.4×77
1064.8cm₂
TSA of cylinder =2πRh+2πrh(R₂-r₂)
1064.8+2×22÷7×2×77+2×22÷7×[(2.2)₂-(2)₂]
1064.8+968+2×22÷7×(4.84-4)
1064.8+968+2×2×22÷7×0.84
1064.8+968+5.28=2038.08cm₂
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