a metal pipe is 77cm long the inner diameter of a cross-section sports and the outer diameter being 4.4 cm find its Bal in a curve in a curved surface area to Outer curved surface area 3 total surface area
Answers
Answer:
There is a inner Cylinder and Outer Cylinder.
Inner Radius = Inner Diameter / 2 = 4 / 2 = 2 cm = r
Outer Radius = Outer Diameter / 2 = 4.4/2 = 2.2 cm = R
Height of the pipe = 77 cm = h
Inner Surface area of the Pipe = 2∏rh = 2*22*2*77/7 = 968 Square cm.
Outer Surface area of the pipe = 2∏Rh = 2*22*2.2*77/7 = 1064.8 Square cm.
Total Surface area = Inner Surface area + Outer Surface area + 2 * Cross section surface area.
The cross section suface area is present at two ends of the pipe.
This is the area covered between 2 circles.
Total Surface area = Inner Surface area + Outer Surface area + 2 * Cross section surface area.
= 968 + 1064.8 + 2*∏(R^2 – r^2)
= 2032.8 + 2*22*(2.2*2.2 – 2*2)/7
= 2032.8 + 5.28
= 2038.08 Square cm
Inner Surface area of the Pipe = 968 Square cm.
Outer Surface area of the pipe = 1064.8 Square cm.
Total Surface Area = = 2038.08 Square cm.