Question

A metal pipe is 77cm. Long.The inner diameter of cross section is 4cm.,the outer diameter being 4.4 cm.Find its (i) inner curved surface area (ii) outer curved surface area (iii)total surface area

Answer 1

Step-by-step explanation:

$\huge{\bold{\red{\underline{\mathcal{Part1}}}}}$

inner radius = 4/2 = 2

1) inner curved surface area = 2πrh

= 2* 22/7 * 2 * 77

$\frac{2 \times 22 \times 2 \times 77}{7}$

$2 \times 22 \times 2 \times 11$

968 cm²

$\huge{\red{\bold{\underline{\mathcal{Part2}}}}}$

outer radius = 2.2

2)outer curved surface area = 2πrh

= 2*22/7 * 2.2 * 77

$\frac{2 \times 22 \times 2.2 \times 77}{7}$

1064.8 cm²

$\huge{\red{\bold{\underline{\mathcal{Part3}}}}}$

3)total surface area = SA of inner +SA of outer + 2π(R²-r²)

968+1064.8 + 2* 22/7 (2.2² -2²)

2032.8 + 2*22/7 * 0.84

2032.8+5.28

2038.08cm²

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