A metal pipe is 77cm long, the inner diameter of the cross section is 4cm and the outer diameter is 4.8cm find it’s TSA
Answers
Answer:
Use Formula of TSA:-πr^2h
Step-by-step explanation:
1.First find tsa of inner.
2.Then find tsa of outer.
3.Add both the Tsa.
4.You will get the tsa
- Height of pipe = 77cm
- Inner Diameter = 4cm
- Outer Diameter = 4cm
- Total Surface Area of Cylinder.
Here, f1st we will find the Inner Curved surface area:-
→ Radius, r₁ = 4/2 = 2cm
By using
↦ Curved surface area = 2 πr₁h
where,
- π = 22/7
- r₁ = 2cm
- h = 77cm
☆ substituting these values:
↣Inner Curved Surface Area = 2 πr₁h
↣Inner Curved Surface Area = 2×22/7×2×77
↣Inner Curved Surface Area = 4×22×11
↣Inner Curved Surface Area = 968cm²
So, Inner Curved surface area is 968cm²
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Now, finding outer curved surface area:-
→ Radius, r₂ = 4.8/2 = 2.4cm
Again, Using
↦ Curved surface area = 2 πr₂h
where,
- π = 22/7
- r₂ = 2.4cm
- h = 77cm
☆ substituting these values:
↪Outer Curved surface area = 2 πr₂h
↪Outer Curved surface area = 2×22/7×2.4×77
↪Outer Curved surface area = 44 × 24/10 × 11
↪Outer Curved surface area = 11616/10
↪Outer Curved surface area = 1161.6cm²
So, outer curved surface area is 1161.6cm²
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Now, finding base area:
By using
↦ Area of base = π(r₂² - r₁²)
where,
- π = 22/7
- r₁ = 2cm
- r₂ = 2.4cm
☆ substituting these values:
↝ Area of base = π(r₂² - r₁²)
↝ Area of base = 22/7[(2.4)² - (2)²]
↝ Area of base = 22/7[5.76 - 4]
↝ Area of base = 22/7[1.76]
↝ Area of base = 38.72/7 = 5.531(approx.)cm²
↝ Area of base = 5.53cm²
________________________
Now, atlast finding Total Surface Area:
↬ Total Surface Area = Inner C.S.A + Outer C.S.A + 2(Area of base)
where,
- Inner C.S.A = 968cm²
- Outer C.S.A = 1161.6cm²
- Area of base = 5.53cm²
☆ substituting these values:
⇝ Total Surface Area = Inner C.S.A + Outer C.S.A + 2(Area of base)
⇝Total Surface Area = 968 + 1161.6 + 5.53
⇝Total Surface Area = 2135.13cm²