A metal plate weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwardsfrom below. After collision ball rebounds with same speed with which balls strike the plate? [Given: mass of each ball =200g and g=10m/s^2] 1) 5.7 cm/s 2) 12.5 cm/s 3) 9.8 cm/s 4) 14 cm/s
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HEY DEAR ...
Given : Mass of Plate = 0.2 Kg
Mass of Each Ball = 0.2 Kg
No. of Ball thrown = 40
The plate is balanced so the force exterted by plate is equal to the force of 40 balls
= Mg = 40 x mv/t
= 0.2 x 10 = 40 x 0.2 x v/1(t=1 sec)
= v = 0.25 m/sec
HOPE , IT HELPS ... ✌️
Given : Mass of Plate = 0.2 Kg
Mass of Each Ball = 0.2 Kg
No. of Ball thrown = 40
The plate is balanced so the force exterted by plate is equal to the force of 40 balls
= Mg = 40 x mv/t
= 0.2 x 10 = 40 x 0.2 x v/1(t=1 sec)
= v = 0.25 m/sec
HOPE , IT HELPS ... ✌️
gitasharma:
But answer is 12.5 cm/sec
Answered by
2
Answer:
Explanation:
Given : Mass of Plate = 0.2 Kg
Mass of Each Ball = 0.2 Kg
No. of Ball thrown = 40
The plate is balanced so the force exterted by plate is equal to the force of 40 balls
= Mg = 40 x mv/t
= 0.2 x 10 = 40 x 0.2 x v/1(t=1 sec)
= v = 0.25 m/sec
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