A metal plate weighing 200g is balanced in midair by throwing 40 balls per second vertically upwards from below. After collision ball rebounds with same speed with which balls strike the plate? [Given: mass of each ball =200g and g=10 m/s^2] 1) 5.7 cm/s 2) 12.5 cm/s 3) 9.8 cm/s 4) 14 cm/s
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Answer:
Given : Mass of Plate = 0.2 Kg
Mass of Each Ball = 0.2 Kg
No. of Ball thrown = 40
The plate is balanced so the force exterted by plate is equal to the force of 40 balls
= Mg = 40 x mv/t
= 0.2 x 10 = 40 x 0.2 x v/1(t=1 sec)
= v = 0.25 m/sec
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