A metal rod, 1.8m long increases in length by 1.4 mm when heated from 0°C to 50°C. Find the coefficient of linear expansion of metal.
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Dear Akhil,
◆ Answer -
α = 1.55×10^-5 /℃
◆ Explanation -
# Given -
L° = 1.8 m
l = 1.4 mm = 1.4×10^-3 m
T1 = 0 ℃
T2 = 50 ℃
# Solution -
Let α be the coefficient of linear expansion for the metal.
l = L°α∆T
Substituting values,
1.4×10^-3 = 1.8 × α × (50 - 0)
α = 1.4×10^-3 ÷ 90
α = 1.55×10^-5 /℃
Hence, coefficient of linear expansion of metal is 1.55×10^-5 /℃.
Hope this helped you.
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