Question

A metal rod has length of one metre at 30 degree Celsius Alpha of of metal is is 2.5 into to 10 power minus 5 per degree Celsius the temperature at which it will be shortened by 1 millimetre is

Answer 1

Answer:

Explanation:Δl=α×l1(t1-t2)

0.001=2.5×10∧-5×1(30-t2)

-0.025t2=-0.25

t2=0.25÷0.025

t2=10 degree C

Answer 2

Answer:

-10 degree

Change in length =lα(change in temperature)