Question

A metal rod of 25 cm length is moving at a
speed of 0.5/sec in direction perpendicular to
0.25T magnetic field. Emf produced in the rod is?​

Answer 1

$\huge \mathfrak{Solution:-}$

It is given by formula; vBl sin(theta) = emf, (As theta is 90, so sin 90 = 1)

v = velocity, B = magnetic field, l = length of rod.

SO, emf = (0.25 m) × 0.25 T × 0.5 sec = 0.0312 V.!

Answer 2

Answer:

The correct answer is 0.0312.

Explanation:

From the following formula,

vBl sin(theta) = emf

As we know that the direction is perpendicular,

SO,

It shows that here theta is 90, sin 90 = 1    

SO, emf = (0.25 m) × 0.25 T × 0.5 sec = 0.0312 V.