A metal rod of length 2m rotates vertically about one of its end with frequency 2hz. The horizontal component of earth's magnetic field is 3.14 x 10-5 t then emf developed between two ends of rod is
Answers
Answered by
0
EMF developed between two ends of rod is e = 7.89 × 10–4 V.
Explanation:
Given data:
ℓ = 2 m
f = 2 Hz
BH = 3.14 × 10^–5 T
ω = 2πf = 2π × 2 = 12.56 rad/sec
For a rotating rod. emf induced = [{Bωℓ^2}/2]
e = [{3.14 × 10^–5 ×12.56 × (2)^2}/2]
= 78.9 × 10^–5 V
e = 7.89 × 10^–4 V
Thus emf developed between two ends of rod is e = 7.89 × 10–4 V.
Also learn more
What is E.M.F.?
https://brainly.in/question/2936894
Similar questions