A metal rod of length 50 cm having mass 2 kg is supported on two edges placed 10cm from each end and 3 kg load is suspended at 20 cm from one end find the reactions at the edges.(take g= 10 m/s^2)
(☺Question from SYstem of particles and rotational motion)
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Answer ⤵️
The angular acceleration by a motor that increases speed from 600 rpm to 1200 rpm is
Explanation:
The change in acceleration is 1200 rpm - 600rpm = 600rpm
The change in time = 10 seconds
→First step: Convert the speed from revolutions per minute (rpm) to radians per second (rds/s)
Conversion factor : 60/2π rpm = 1 rad/s
If 60/2π( ( = 9.5481) rpm = 1 rads
Then 600 rpm = 1 rad/sec × 600 rpm/ 9.5481 rpm
⇒600 ÷ 60/(2×3.142) × 1 rad/s
= 62.84 rad/sec
→Second step: Calculate acceleration by the angular acceleration formula
Angular acceleration = Δ angular speed / Δ Time
62.84 rad/s / 10 s
= 6.284 rads/ sec²