Question

A metal rod of length L meter rotates about one end in a vertical plane at right angles to the magnetic meridian.Frequency of revolution is f hz.If the horizontal component of earths magnetic field is H tesla then find the expression of induced emf between the ends of the rod.​

Answer 1

Explanation:

given, length=L meter

frequency = f Hz

Now, Emf, E= 1/2 Bh wl^2

where w=2πu

So, E=1/2 Bh L^2 *2πf

therefore, E=Bh L^2 πf