Question

A metal rod of resistance 15 ohm is moved to the right at a constant speed 60 cm/s along two parallel conducting rails 2cm apart and shorted at one end. A magnetic field of magnitude 0.35 T points into the page. Calculate the induced emf.​

Answer 1

Answer:

(a) Equation E=

dt

dΦ

B

=

dt

d

BLx=BL

dt

dx

=BLv leads to

ε=BLv=(0.350T)(0.250m)(0.55m/s)=0.0481V

(b) By Ohm's law, the induced current is

i=0.0481V/18.0Ω=0.00267A

By Lenz's law, the current is clockwise in Figure.

(c) Equation P=i

2

R (resistive dissipation) leads to P=i

2

R=0.000129W

Step-by-step explanation: