a metal rod of resistance 15 ohmis moved to right at constant speed 60cm/s along two parellel conducting rails 2cm apart and shorted at one end a magnetic field magnetude 0.35 T points into page .calculate the induced emf
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it is a example not a answer ok
(a) Equation E=
dt
dΦ
B
=
dt
d
BLx=BL
dt
dx
=BLv leads to
ε=BLv=(0.350T)(0.250m)(0.55m/s)=0.0481V
(b) By Ohm's law, the induced current is
i=0.0481V/18.0Ω=0.00267A
By Lenz's law, the current is clockwise in Figure.
(c) Equation P=i
2
R (resistive dissipation) leads to P=i
2
R=0.000129W
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