Question

A metal rod of resistance 20Ω is fixed along the diameter of a conducting ring of radius0.1m . A magnetic field of B=50T acts perpendicular to the plane The ring rotates with an angular velocity of w=20rad/s about its axis . An external resistance of 10Ω is connected across center and rim of the ring. What is current through the external resistance.

Answer 1

Potential difference between centre and rim of the ring is

V=12V=12Bwr2Bwr2

=12=1250.20×(.1)250.20×(.1)2

=5V=5V

Now the equivalent circuit is :

i=510+5i=510+5

=13=13AA