Question

A metal rod of Young's modulus 2 × 10¹⁰ Nm⁻² undergoes an elastic strain of 0.06%. The energy per unit volume stored in Jm⁻³ is(a) 3600(b) 7200(c) 10800(d) 14400

Answer 1

Answer:

a) 3600

Explanation:

Strain=0.06/100

Young's modulus (Y)= 2 × 10¹⁰ Nm⁻²

Thus,

Energy = 1/2×stress×strain×volume

Energy/volume = 1/2×stress×strain

= 1/2×γ×strain²

= 1/2×2×10¹⁰×(0.06/100)²

= 10¹⁰×36/ 10 to the power 8

= 10²×36

= 3600

Hence, the energy per unit volume stored is 3600