A metal rod of Young's modulus 2 × 10¹⁰ Nm⁻² undergoes an elastic strain of 0.06%. The energy per unit volume stored in Jm⁻³ is(a) 3600(b) 7200(c) 10800(d) 14400
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Answer:
a) 3600
Explanation:
Strain=0.06/100
Young's modulus (Y)= 2 × 10¹⁰ Nm⁻²
Thus,
Energy = 1/2×stress×strain×volume
Energy/volume = 1/2×stress×strain
= 1/2×γ×strain²
= 1/2×2×10¹⁰×(0.06/100)²
= 10¹⁰×36/ 10 to the power 8
= 10²×36
= 3600
Hence, the energy per unit volume stored is 3600
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