a metal sheet is of 4m*3m size what is the increase in its surface area when heated through 80°C？given the cofficent of superficial expansion of the metal is 2.4*20^-5/°C
Answers
Answer:
Increase in surface area is 0.00144 m^2
Explanation:
Formula for linear expansion of a metal is;
L = L initial ( 1 + α (t2 – t1))
Linitial is the initial length at temperature t1, t2 is the final temperature and α is the cofficent of thermal expansion expansion.
We now apply this formula for length 3 and 4 meters.
L = 3 (1 + α (80))
Here we are given that α = 2.4*20^-5 = 0.00000075
L = 3 (1 + 0.00000075 (80))
L’ = 3.00018
Similarly for dimension 4 m
L’ = 4 (1 + 0.00000075 (80))
L’ = 4.00024
Now original area was;
A = 3 x 4 = 12 m^2
After expansion, area will be;
A’ = 4.00024 x 3.00018
A’ = 12.00144 m^2
Net increase in area will be;
= A’ – A
= 0.00144 m^2
Answer:
Increase in surface area is 0.00144 m^2
Explanation:
Formula for linear expansion of a metal is;
L = L initial ( 1 + α (t2 – t1))
Linitial is the initial length at temperature t1, t2 is the final temperature and α is the cofficent of thermal expansion expansion.
We now apply this formula for length 3 and 4 meters.
L = 3 (1 + α (80))
Here we are given that α = 2.4*20^-5 = 0.00000075
L = 3 (1 + 0.00000075 (80))
L’ = 3.00018
Similarly for dimension 4 m
L’ = 4 (1 + 0.00000075 (80))
L’ = 4.00024
Now original area was;
A = 3 x 4 = 12 m^2
After expansion, area will be;
A’ = 4.00024 x 3.00018
A’ = 12.00144 m^2
Net increase in area will be;
= A’ – A
= 0.00144 m^2
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