Question

a metal spanner has a mass of 200g (0.2 kg), it is lowered into a measuring cylinder of water until it is completely submerged, the original level of the water was 50 cm cubed (^3) and the final level is 75 cm cubed (^3).. calculate the volume of the metal..

Answer 1

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Thus: by dividing the less dense object by the denser fluid displaced, the percentage volume of the object that is submerged, which is equal to the volume of displaced water, is determined. Subtracting 100 from this give the percentage that floats.