Math, asked by fabulouslincom, 10 months ago

A metal sphere 6cm in diameter is melted and cast into balls of diameter 0.5cm.How many of the smaller balls will there be?

Answers

Answered by BrainlyConqueror0901
26

{\bold{\underline{\underline{Answer:}}}}

{\bold{\therefore No.\:of\:balls=1728}}

{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

• In the given question information given about a metal sphere 6cm in diameter is melted and cast into balls of diameter 0.5cm.

• We have to find no. of smaller balls .

 \underline \bold{Given : } \\  \implies Diameter \: of \: sphere = 6 \: cm \\  \\ \underline \bold{To \: find : }  \\ \implies No. \: of \: balls \: of \: diameter \: 0.5 \: cm = ?

• According to given question :

 \bold{Radius=  \frac{6}{2}   = 3 \: cm}\\   \\ \bold{Using \: formula\:  volume \: of \: sphere : } \\  \implies  Volum e\: of \: sphere =  \frac{4}{3} \pi {r}^{3}  \\  \\  \implies  Volume_{1}  =  \frac{4}{3} \pi  \: ({3})^{3}  \\  \\  \implies Volume_{1} = 36\pi \:  {cm}^{3}  \\  \\   \bold{For \: Volume \: of \: small \: sphere : } \\  \implies Volume_{2} =  \frac{4}{3} \pi \:  ({ \frac{0.5}{2} })^{3}  \\  \\  \implies Volume_{2} =  \frac{4}{3} \pi \:  \frac{0.125}{8}  \\  \\  \implies Volume_{2} =  \frac{0.125}{6} \pi  \: {cm}^{2}  \\  \\  \bold{For \: no. \: of \: balls : } \\  \implies No. \: of \: balls =  \frac{Volume_{1}}{Volume_{2}}  \\  \\  \implies No. \: of \: balls =  \frac{36\pi}{ \frac{0.125}{6}\pi }  \\  \\  \implies No. \: of \: balls =  \frac{36 \times 6 \times \cancel\pi}{0.125 \times \cancel\pi}  \\  \\   \bold{\implies  No. \: of \: balls = 1728 \: balls}

Answered by ram5556
12

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