Question

A metal sphere of radius 10cm has a charge of 12.56×10-6c . The surface charge density on the sphere is

Answer 1

Given that ,

• The radius of sphere (r) = 10 cm
• Charge (q) = 12.56 × (10)^-6 C

We know that ,

$\sf \large\fbox{Surface \: charge \: density = \frac{charge}{area} }$

Thus ,

$\sf \mapsto Surface \: charge \: density = \frac{12.56 \times {(10)}^{ - 6} }{4 \times 3.14\times 0.01 } \\ \\\sf \mapsto Surface \: charge \: density =\frac{3.14 \times {(10)}^{ - 4} }{3.14} \\ \\\sf \mapsto Surface \: charge \: density = {(10)}^{ - 4} \: \: c/ {m}^{2}$

$\sf \therefore \underline{The \: surface \: charge \: density \: on \: the \: sphere \: is \: {(10)}^{ - 4} \: c/ {m}^{2} }$