Math, asked by shri8626, 1 year ago

A metal sphere of radius 12 cm is melted into three smaller sphere of the radii of two space of 6 and 8 cm the radius of the third is

Answers

Answered by haridasan85
2

vol of metalsphere = 4/3πr^3

= 4/3xπx12^3=2304π

Total vol of the 3 small spheres/ =

4/3πx6^3+4/3πx8^3+4/3πx^3

(here X is the radius which is to be calculated)

2304π = 4/3π(6^3+8^3+x^3)

6^3+8^3+x^3=2304,πx3/.4π

216+512+x^3=1728

728+x^3=1728

x^3=1728-728

X^3=1000

x = 3 v1ooo

x=10

RadiusX of the smaller sphere

is 10cm. Ans

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