Question

a metal surface is illuminated by light of given intensity and frequency to cause photoemission. if the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoeletrons would be
(a) twice the original value
(b) four times the original value
(c) one fourth of the original value
(d) unchanged ​

Answer 1

hlw buddy ur answer may be option D

Answer 2

option (d) is the correct answer.