Question

A metal that exists ,as a liquid at room temperature is obtained by heating its sulphide in the presence of air identify the metal and its ore and give the reaction involved​

Answer 1

The metal is mercury. It’s ore is cinnabar (HgS)

2HgS +3 O2 ⇒2 HgO + 2SO2. (roasting)

2HgO ⇒ (heated) 2Hg + O2. (Heating)

Answer 2

The metal is Mercury. It’s sulphide ore is Cinnabar (HgS). The reaction involved is as follows:

2HgS + 3O2= 2HgO + 2SO2

2HgO=(under high temperature) 2Hg + O2